Homework 10
Due at 11:59:59 pm on Friday, 11/19/2021.
Linked Lists
A linked list is either an empty linked list (Link.empty
) or a first value
and the rest of the linked list.
class Link:
"""
>>> s = Link(1, Link(2, Link(3)))
>>> s
Link(1, Link(2, Link(3)))
"""
empty = ()
def __init__(self, first, rest=empty):
assert rest is Link.empty or isinstance(rest, Link)
self.first = first
self.rest = rest
def __repr__(self):
if self.rest is not Link.empty:
rest_str = ', ' + repr(self.rest)
else:
rest_str = ''
return 'Link({0}{1})'.format(repr(self.first), rest_str)
To check if a Link
is empty, compare it against the class attribute
Link.empty
. For example, the below function prints out whether or not the link it is handed is empty:
def test_empty(link):
if link is Link.empty:
print('This linked list is empty!')
else:
print('This linked list is not empty!')
Note: Linked lists are recursive data structures! A linked list contains the first element of the list (
first
) and a reference to another linked list (rest
) which contains the rest of the values in the list.
Question 1: Link to List
Write a function link_to_list
that converts a given Link
to a
Python list.
def link_to_list(link):
"""Takes a Link and returns a Python list with the same elements.
>>> link = Link(1, Link(2, Link(3, Link(4))))
>>> link_to_list(link)
[1, 2, 3, 4]
>>> link_to_list(Link.empty)
[]
"""
"*** YOUR CODE HERE ***"
Use OK to test your code:
python3 ok -q link_to_list
Question 2: Every Other
Implement every_other
, which takes a linked list s
. It mutates s
such
that all of the odd-indexed elements (using 0-based indexing) are removed from
the list. For example:
>>> s = Link('a', Link('b', Link('c', Link('d'))))
>>> every_other(s)
>>> s.first
'a'
>>> s.rest.first
'c'
>>> s.rest.rest is Link.empty
True
If s
contains fewer than two elements, s
remains unchanged.
Do not return anything!
every_other
should mutate the original list.
def every_other(s):
"""Mutates a linked list so that all the odd-indiced elements are removed
(using 0-based indexing).
>>> s = Link(1, Link(2, Link(3, Link(4))))
>>> every_other(s)
>>> s
Link(1, Link(3))
>>> odd_length = Link(5, Link(3, Link(1)))
>>> every_other(odd_length)
>>> odd_length
Link(5, Link(1))
>>> singleton = Link(4)
>>> every_other(singleton)
>>> singleton
Link(4)
"""
"*** YOUR CODE HERE ***"
Use OK to test your code:
python3 ok -q every_other
Trees
Question 3: Leaves
Write a function leaves
that returns a list of all the entries of the leaf
nodes of a Tree
.
def leaves(t):
"""Returns a list of all the entries of the leaf nodes of the Tree t.
>>> leaves(Tree(1))
[1]
>>> leaves(Tree(1, [Tree(2, [Tree(3)]), Tree(4)]))
[3, 4]
"""
"*** YOUR CODE HERE ***"
Use OK to test your code:
python3 ok -q leaves
Question 4: Path
Write a function path
that returns the path from the root of the tree to the given entry value if it exists and [] if it does not. You can assume all entries are unique.
def path(t, value):
"""
>>> t = Tree(9, [Tree(7, [Tree(3), Tree(2)]), Tree(5)])
>>> path(t, 2)
[9, 7, 2]
>>> path(t, 5)
[9, 5]
>>> path(t, 8)
[]
"""
"*** YOUR CODE HERE ***"
Use OK to test your code:
python3 ok -q path
Question 5: Find Level
Implement find_level
, which takes a tree t
and an integer level
and returns a list of all the entries that have depth level
. If no such entries exists, return the empty list. For a refresher on the depth of a node, check out here.
def find_level(t, level):
"""
>>> t = Tree(1, [Tree(2, [Tree(4), Tree(5)]), Tree(6, [Tree(7)])])
>>> find_level(t, 2)
[4, 5, 7]
>>> find_level(t, 1)
[2, 6]
>>> find_level(t, 5)
[]
"""
"*** YOUR CODE HERE ***"
Use OK to test your code:
python3 ok -q find_level
Submit
Make sure to submit this assignment by running:
python3 ok --submit