Lab 4: Recursion
Due by 11:59pm on Friday, September 27.
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Required Questions
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Recursion
Q1: Double Eights
Write a recursive function that takes in a positive integer n
and determines if its
digits contain two adjacent 8
s (that is, two 8
s right next to each other).u
Hint: Start by coming up with a recursive plan: the digits of a number have double eights if either (think of something that is straightforward to check) or double eights appear in the rest of the digits.
Important: Use recursion; the tests will fail if you use any loops (for, while).
def double_eights(n):
"""Returns whether or not n has two digits in row that
are the number 8.
>>> double_eights(1288)
True
>>> double_eights(880)
True
>>> double_eights(538835)
True
>>> double_eights(284682)
False
>>> double_eights(588138)
True
>>> double_eights(78)
False
>>> # ban iteration
>>> from construct_check import check
>>> check(LAB_SOURCE_FILE, 'double_eights', ['While', 'For'])
True
"""
"*** YOUR CODE HERE ***"
Use Ok to test your code:
python3 ok -q double_eights
Q2: Summation
Write a recursive implementation of summation
, which takes a positive
integer n
and a function term
. It applies term
to every number from 1
to n
including n
and returns the sum.
Important: Use recursion; the tests will fail if you use any loops (for, while).
def summation(n, term):
"""Return the sum of numbers 1 through n (including n) wíth term applied to each number.
>>> summation(5, lambda x: x * x * x) # 1^3 + 2^3 + 3^3 + 4^3 + 5^3
225
>>> summation(9, lambda x: x + 1) # 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10
54
>>> summation(5, lambda x: 2**x) # 2^1 + 2^2 + 2^3 + 2^4 + 2^5
62
>>> # ban iteration
>>> from construct_check import check
>>> check(LAB_SOURCE_FILE, 'summation', ['While', 'For'])
True
"""
assert n >= 1
"*** YOUR CODE HERE ***"
Use Ok to test your code:
python3 ok -q summation
Q3: Ten-Pairs
Write a function that takes a positive integer n
and returns the
number of ten-pairs it contains. A ten-pair is a pair of digits
within n
that sums to 10.
The number 7,823,952 has 3 ten-pairs. The first and fourth digits sum to 7+3=10, the second and third digits sum to 8+2=10, and the second and last digit sum to 8+2=10.
Important notes:
- A digit can be part of more than one ten-pair.
- One 5 does not make a ten-pair with itself.
Recommended: Complete and use the helper function
count_digit
to calculate how many times a digit appears inn
.
Important: Use recursion; the tests will fail if you use any loops (for, while).
def ten_pairs(n):
"""Return the number of ten-pairs within positive integer n.
>>> ten_pairs(7823952)
3
>>> ten_pairs(55055)
6
>>> ten_pairs(9641469)
6
>>> # ban iteration
>>> from construct_check import check
>>> check(LAB_SOURCE_FILE, 'ten_pairs', ['While', 'For'])
True
"""
"*** YOUR CODE HERE ***"
def count_digit(n, digit):
"""Return how many times digit appears in n.
>>> count_digit(55055, 5)
4
>>> from construct_check import check
>>> # ban iteration
>>> check(LAB_SOURCE_FILE, 'count_digits', ['While', 'For'])
True
"""
"*** YOUR CODE HERE ***"
Use Ok to test your code:
python3 ok -q ten_pairs
Check Your Score Locally
You can locally check your score on each question of this assignment by running
python3 ok --score
This does NOT submit the assignment! When you are satisfied with your score, submit the assignment to Gradescope to receive credit for it.
Submit Assignment
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