Lab 4: Lambdas, Dictionaries, and ADTs
Due at 11:59:59 pm on 2/23/2020.
Starter Files
Download lab04.zip. Inside the archive, you will find starter files for the questions in this lab, along with a copy of the OK autograder.
Submission
By the end of this lab, you should have submitted the lab with python3 ok --submit
. You may submit more than once before the deadline; only the final submission will be graded. Check that you have successfully submitted your code on okpy.org. See this article for more instructions on okpy and submitting assignments.
- To receive full credit for this lab, all questions must be attempted.
When you are ready to submit, run ok
with the --submit
option:
python3 ok --submit
After submitting, ok
will display a submission URL, with which you can view your submission on okpy.org.
Lambda
Lambda
expressions are one-line functions that specify two things:
the parameters and the return value.
lambda <parameters>: <return value>
While both lambda
and def
statements are related to functions, there are some differences.
lambda | def | |
---|---|---|
Type | lambda is an expression |
def is a statement |
Description | Evaluating a lambda expression does not create or modify any variables.
Lambda expressions just create new function objects. |
Executing a def statement will create a new function object and bind it to a variable in the current environment. |
Example |
|
|
A lambda
expression by itself is not very interesting. As with any objects such as numbers, booleans, strings, we usually:
- assign lambda to variables (
foo = lambda x: x
) - pass them in to other functions (
bar(lambda x: x)
) - return them as the results of other functions (
return lambda x: x
) - return them as the results of other lambdas (
lambda x: lambda y: x + y
)
In the final example above, the outer lambda (lambda x
) takes in a value x
, and it
returns another lambda (lambda y
) that takes an argument y
and returns x+y
.
Environment Diagrams
Environment diagrams are one of the best learning tools for understanding
lambda
expressions because you're able to keep
track of all the different names, function objects, and arguments to functions.
We highly recommend drawing environment diagrams or using Python
tutor if you get stuck doing the WWPD problems below.
For examples of what environment diagrams should look like, try running some
code in Python tutor. Here are the rules:
Lambdas
Note: As we saw in the
lambda
expression section above,lambda
functions have no intrinsic name. When drawinglambda
functions in environment diagrams, they are labeled with the namelambda
or with the lowercase Greek letter λ. This can get confusing when there are multiple lambda functions in an environment diagram, so you can distinguish them by numbering them or by writing the line number on which they were defined.
- Draw the lambda function object and label it with λ, its formal parameters, and its parent frame. A function's parent frame is the frame in which the function was defined.
This is the only step. We are including this section to emphasize the fact that
the difference between lambda
expressions and def
statements is that
lambda
expressions do not create any new bindings in the environment.
WWPD
Question 1: WWPD: Lambda the Free
Use Ok to test your knowledge with the following "What Would Python Display?" questions:
python3 ok -q lambda -u
For all WWPD questions, type
Function
if you believe the answer is<function...>
,Error
if it errors, andNothing
if nothing is displayed. As a reminder, the following two lines of code will not display anything in the Python interpreter when executed:>>> x = None >>> x
>>> lambda x: x # A lambda expression with one parameter x
______<function <lambda> at ...>
>>> a = lambda x: x # Assigning the lambda function to the name a
>>> a(5)
______5
>>> (lambda: 3)() # Using a lambda expression as an operator in a call exp.
______3
>>> b = lambda x: lambda: x # Lambdas can return other lambdas!
>>> c = b(88)
>>> c
______<function <lambda> at ...
>>> c()
______88
>>> d = lambda f: f(4) # They can have functions as arguments as well.
>>> def square(x):
... return x * x
>>> d(square)
______16
>>> z = 3
>>> e = lambda x: lambda y: lambda: x + y + z
>>> e(0)(1)()
______4
>>> f = lambda z: x + z
>>> f(3)
______NameError: name 'x' is not defined
>>> higher_order_lambda = lambda f: lambda x: f(x)
>>> g = lambda x: x * x
>>> higher_order_lambda(2)(g) # Which argument belongs to which function call?
______Error
>>> higher_order_lambda(g)(2)
______4
>>> call_thrice = lambda f: lambda x: f(f(f(x)))
>>> call_thrice(lambda y: y + 1)(0)
______3
>>> print_lambda = lambda z: print(z) # When is the return expression of a lambda expression executed?
>>> print_lambda
______Function
>>> one_thousand = print_lambda(1000)
______1000
>>> one_thousand
______# print_lambda returned None, so nothing gets displayed
Lambda
Question 2: Compose
Write a function that takes in 2 single-argument functions, f and g, and returns another lambda function that takes in a single argument x. The returned function should return the output of applying f(g(x)).
Hint: The staff solution is only 1 line!
def compose(f, g):
"""Write a function that takes in 2 single-argument functions, f and g, and returns another lambda function
that takes in a single argument x. The returned function should return the output of applying f(g(x)).
Hint: The staff solution is only 1 line!
Return the composition function which given x, computes f(g(x)).
>>> add_two = lambda x: x + 2 # adds 2 to x
>>> square = lambda x: x ** 2 # squares x
>>> a = compose(square, add_two) # (x + 2 ) ^ 2
>>> a(5)
49
>>> mul_ten = lambda x: x * 10 # multiplies 10 with x
>>> b = compose(mul_ten, a) # ((x + 2 ) ^ 2) * 10
>>> b(5)
490
>>> b(2)
160
"""
"*** YOUR CODE HERE ***"
return lambda x: f(g(x))
Use OK to test your code:
python3 ok -q compose
Question 3: Mul_by_num
Using a lambda
expression, complete the mul_by_num
function. This
function should take an argument and return a one argument function
that multiplies any value passed to it by the original number. Its
body must be one line long:
def mul_by_num(num):
"""
Returns a function that takes one argument and returns num
times that argument.
>>> x = mul_by_num(5)
>>> y = mul_by_num(2)
>>> x(3)
15
>>> y(-4)
-8
"""
"*** YOUR CODE HERE ***"
return lambda num2: num * num2
Use OK to test your code:
python3 ok -q mul_by_num
Abstract Data Types
Data abstraction is a powerful concept in computer science that allows programmers to treat code as objects --- for example, car objects, chair objects, people objects, etc. That way, programmers don't have to worry about how code is implemented --- they just have to know what it does.
Data abstraction mimics how we think about the world. For example, when you want to drive a car, you don't need to know how the engine was built or what kind of material the tires are made of. You just have to know how to turn the wheel and press the gas pedal.
An abstract data type consists of two types of functions:
- Constructors: functions that build the abstract data type.
- Selectors: functions that retrieve information from the data type.
For example, say we have an abstract data type called city
.
This city
object will hold the city
's name, and
its latitude and longitude. To create a city
object,
you'd use a constructor like
city = make_city(name, lat, lon)
To extract the information of a city
object, you would use the selectors like
get_name(city)
get_lat(city)
get_lon(city)
For example, here is how we would use the make_city
constructor to create a city object to represent Berkeley
and the selectors to access its information.
>>> berkeley = make_city('Berkeley', 122, 37)
>>> get_name(berkeley)
'Berkeley'
>>> get_lat(berkeley)
122
>>> get_lon(berkeley)
37
Notice that we don't need to know how these functions were implemented. We are assuming that someone else has defined them for us.
It's okay if the end user doesn't know how functions were implemented. However, the functions still have to be defined by someone. We'll look into defining the constructors and selectors later in this discussion.
Question 4: Distance
We will now use those selectors to write distance
, which computes the distance between two city objects. Recall that the distance between two coordinate pairs, (x1, y1)
and (x2, y2)
can be found by calculating the sqrt
of (x1 - x2)**2 + (y1 - y2)**2
. We have already imported sqrt
for your convenience, so use that and the appropriate selectors to fill in the function.
from math import sqrt
def distance(city_1, city_2):
"""
>>> city1 = make_city('city1', 0, 1)
>>> city2 = make_city('city2', 0, 2)
>>> distance(city1, city2)
1.0
"""
"*** YOUR CODE HERE ***"
lat_1, lon_1 = get_lat(city_1), get_lon(city_1)
lat_2, lon_2 = get_lat(city_2), get_lon(city_2)
return sqrt((lat_1 - lat_2)**2 + (lon_1 - lon_2)**2)
Use OK to test your code:
python3 ok -q distance
Question 5: Closer city
Implement closer_city
, a function that takes a latitude,
longitude, and two cities, and returns the name of the city that is
relatively closer to the provided latitude and longitude.
You may only use selectors and constructors (introduced above) for
this question. You may also use the distance
function
defined above. Remember, the point of data abstraction,
as we've said, is that we do not need to know how an abstract data type is
implemented, but rather just how we can interact with and use the data type.
def closer_city(lat, lon, city1, city2):
""" Returns the name of either city1 or city2, whichever is closest
to coordinate (lat, lon).
>>> berkeley = make_city('Berkeley', 37.87, 112.26)
>>> stanford = make_city('Stanford', 34.05, 118.25)
>>> closer_city(38.33, 121.44, berkeley, stanford)
'Stanford'
>>> bucharest = make_city('Bucharest', 44.43, 26.10)
>>> vienna = make_city('Vienna', 48.20, 16.37)
>>> closer_city(41.29, 174.78, bucharest, vienna)
'Bucharest'
"""
"*** YOUR CODE HERE ***"
return <REPLACE THIS>
new_city = make_city('arb', lat, lon)
dist1 = distance(city1, new_city)
dist2 = distance(city2, new_city)
if dist1 < dist2:
return get_name(city1)
return get_name(city2)
Use OK to test your code:
python3 ok -q closer_city
Question 6: Closer City Abstraction
Run the following ok test to make sure that you are using abstraction barriers correctly! You should not need to change your code from the previous question to pass this test.
Use OK to test your code:
python3 ok -q check_abstraction
Dictionaries
You've actually seen several abstract data types! List, tuples, ranges, and even strings are examples of abstract data types. Dictionary is another example of abstract data types.
Dictionaries are unordered sets of key-value pairs. To create a dictionary, use the following syntax:
>>> singers = { 'Iggy Azalea': 'Fancy', 'Beyonce': 'Flawless', 'Adam Levine': 'Maps'}
The curly braces denote the key-value pairs in your dictionary. Each key-value pair is separated by a comma. For each pair, the key appears to the left of the colon and the value appears to the right of the colon. (This is a dictionary's constructor!) You can retrieve values from your dictionary by "indexing" using the key:
>>> singers['Beyonce']
'Flawless'
>>> singers['Iggy Azalea']
'Fancy'
You can update an entry for an existing key in the dictionary using the following syntax. What this means is that each key is unique. Be careful, adding a new key follows identical syntax!
>>> singers['Beyonce'] = 'Survivor'
>>> singers['Beyonce']
'Survivor'
>>> singers['Nicki Minaj'] = 'Anaconda' # new entry!
>>> singers['Nicki Minaj']
'Anaconda'
You can also check for membership of keys!
>>> 'Adam Levine' in singers
True
Recall how we can iterate through a list using for-loops. For example, you can do something like this:
>>> a = [1,2,3]
>>> for each in a:
... print(each)
1
2
3
What happens if you iterate through a dictionary? Can you even iterate through a dictionary?? Notice what happens:
>>> shopping_cart = {"apple":3, "bananas":4, "orange":6}
>>> for each in shopping_cart:
... print(each)
apple
bananas
orange
Notice that when you iterate through a dictionary, the set of keys is what you iterate through. How would you print out values instead? You can simply do:
>>> shopping_cart = {"apple":3, "bananas":4, "orange":6}
>>> for each in shopping_cart:
... print(shopping_cart[each])
3
4
5
Question 7: Counter
Implement the function counter
which takes in a string of words, and returns a
dictionary where each key is a word in the message, and each value is the number
of times that word is present in the original string.
def counter(message):
""" Returns a dictionary of each word in message mapped
to the number of times it appears in the input string.
>>> x = counter('to be or not to be')
>>> x['to']
2
>>> x['be']
2
>>> x['not']
1
>>> y = counter('run forrest run')
>>> y['run']
2
>>> y['forrest']
1
"""
word_list = message.split()
"*** YOUR CODE HERE ***"
result_dict = {}
for word in word_list:
if word in result_dict:
result_dict[word] += 1
else:
result_dict[word] = 1
return result_dict
Use OK to test your code:
python3 ok -q counter
Required Practice ProblemsOpen in a new window
These questions are a mix of Parsons Problems, Code Tracing questions, and Code Writing questions.
Confused about how to use the tool? Check out https://codestyle.herokuapp.com/cs88/lab01 for some problems designed to demonstrate how to solve these types of problems.
These cover some similar material to lab, so can be helpful to further review or try to learn the material. Unlike lab and homework, after you've worked for long enough and tested your code enough times on any of these questions, you'll have the option to view an instructor solution. You'll unlock each question one at a time, either by correctly answering the previous question or by viewing an instructor solution.
Use OK to test your code:
python3 ok -q practice_problems
Submit
Make sure to submit this assignment by running:
python3 ok --submit
Optional: Environment Diagram Practice
There is no submission for this component. However, we still encourage you to do these problems on paper to develop familiarity with Environment Diagrams, which will appear on the exam.
Question 8: Make Adder
Draw the environment diagram for the following code:
n = 9
def make_adder(n):
return lambda k: k + n
add_ten = make_adder(n+1)
result = add_ten(n)
There are 3 frames total (including the Global frame). In addition, consider the following questions:
- In the Global frame, the name
add_ten
points to a function object. What is the intrinsic name of that function object, and what frame is its parent? - In frame
f2
, what name is the frame labeled with (add_ten
or λ)? Which frame is the parent off2
? - What value is the variable
result
bound to in the Global frame?
You can try out the environment diagram at tutor.cs61a.org. To see the environment diagram for this question, click here.
- The intrinsic name of the function object that
add_ten
points to is λ (specifically, the lambda whose parameter isk
). The parent frame of this lambda isf1
. f2
is labeled with the name λ the parent frame off2
isf1
, since that is where λ is defined.- The variable
result
is bound to 19.
Question 9: Lambda the Environment Diagram
Try drawing an environment diagram for the following code and predict what Python will output.
You do not need to submit or unlock this question through Ok. Instead, you can check your work with the Online Python Tutor, but try drawing it yourself first!
>>> a = lambda x: x * 2 + 1
>>> def b(b, x):
... return b(x + a(x))
>>> x = 3
>>> b(a, x)
______21 # Interactive solution: https://goo.gl/Lu99QR