#
Homework 8

*Due at 11:59:59 pm on Thursday, 4/7/2022.*

## Instructions

Download hw08.zip. Inside the archive, you will find starter files for the questions in this homework, along with a copy of the OK autograder.

**Submission:** When you are done, submit with `python3 ok --submit`

. You may submit more than once before the deadline; only the final submission will be scored. Check that you have successfully submitted your code on okpy.org.

**Readings:** This homework relies on following references:

Recall that the order of growth of a function expresses how long it takes for the function to run, and is defined in terms of the function's input sizes.

For example, let's say that we have the function `get_x`

which is
defined as follows:

```
def get_x(x):
return x
```

`get_x`

has one expression in it. That one expression takes the same
amount of time to run, no matter what x is, or more importantly, how
large x gets. This is called constant time, or O(1).

The main two ways that a function in your program will get a running time different than just constant time is through either iteration or recursion. Let's start with some iteration examples!

The (simple) way you figure out the running time of a particular while loop is to simply count the cost of each operation in the body of the while loop, and then multiply that cost by the number of times that the loop runs. For example, look at the following method with a loop in it:

```
def foo(n):
i, sum = 1, 0
while i <= n:
sum,i = sum + i, i + 1
return sum
```

This loop has one statement in it `sum, i = sum + i, i + 1.`

This
statement is considered to run in constant time, as none of its
operations rely on the size of the input.
Individually, `sum = sum + 1`

and `i = i + 1`

are both constant time operations.
However, when we're looking at order of growth, we don't add the times
together and get O(2), we take the maximum of
those 2 values and use that as the running time. In 61A, we are not
concerned with how long primitive functions, such as addition,
multiplication, and variable assignment, take in order to run - we are
mainly concerned with *how many more times a loop is
executed* or *how many more recursive calls* occur as
the input increases. In this example, we execute the loop n times, and
for each iteration, we only execute constant time operations, so we get
an order of growth of O(*n*).

Here are a couple of basic functions, along with their running times. Try to understand why they have the given running time.

O(n)

`def bar(n): i, a, b = 1, 1, 0 while i <= n: a, b, i = a + b, a, i + 1 return a`

O(n^2)

`def bar(n): sum = 0 a, b = 0, 0 while a < n: while b < n: sum += (a*b) b += 1 b = 0 a += 1 return sum`

## Efficiency

There is nothing to submit for this part. But doing these problems will be good practice. The solutions are given right below the question. Try covering the solution and see if you can solve the them!

For each question find the asymptotic runtime in big theta notation.

### Question 1

What is the asymptotic run time of the baz function.

```
def baz(n):
i, sum = 1, 0
while i <= n:
sum += bam(i)
i += 1
return sum
def bam(n):
i, sum = 1, 0
while i <= n:
sum += i
i += 1
return sum
```

O(*n*^{2})

### Question 2

```
def bonk(n):
sum = 0
while n >= 2:
sum += n
n = n / 2
return sum
```

O(log(*n*))

### Question 3

This question is very challenging. This is much beyond what we expect you to know for the exam. This is here merely to challenge you.

```
def boink(n):
if n == 1:
return 1
value = 0
i = 0
while i < n:
value += boink(i)
i += 1
return value
```

*Exponential*, e.g. O(2

^{n})

## Inheritance

### Question 4: Errors

It is often said that nothing in life is certain but death and taxes. For a programmer or data scientist, however, nothing is certain but encountering errors.

In Python, there are two primary types of errors, both of which you are likely familiar with: syntax errors and exceptions. Syntax errors occur when the proper structure of the language is not followed, while exceptions are errors that occur during the execution of a program. These include errors such as ZeroDivisionError, TypeError, NameError, and many more!

Under the hood, these errors are based in the concepts of object orientation, and all exceptions are class objects. If you're interested in more detailed explanations of the structure of exceptions as well as how to create your own, check out this article from the Python documentation! In the meantime, we'll implement our own version of an `Error`

class

Complete the `Error`

, `SyntaxError`

, and `ZeroDivisionError`

classes such that
they create the correct messages when called.

- The
`SyntaxError`

and`ZeroDivisionError`

classes inherit from the`Error`

class and add functionality that is unique to those particular errors. Their code is partially implemented for you. - The
`add_code`

method adds a new helpful message to your error, while the`write`

method should print the output that you see when an error is raised. - You can access the parent class methods using the super() function

```
class Error:
"""
>>> err1 = Error(12, "error.py")
>>> err1.write()
error.py:12
"""
def __init__(self, line, file):
"*** YOUR CODE HERE ***"
def format(self):
return self.file + ':' + str(self.line)
def write(self):
print(self.format())
class SyntaxError(Error):
"""
>>> err1 = SyntaxError(17, "lab10.py")
>>> err1.write()
lab10.py:17 SyntaxError : Invalid syntax
>>> err1.add_code(4, "EOL while scanning string literal")
>>> err2 = SyntaxError(18, "lab10.py", 4)
>>> err2.write()
lab10.py:18 SyntaxError : EOL while scanning string literal
"""
type = 'SyntaxError'
msgs = {0 : "Invalid syntax", 1: "Unmatched parentheses", 2: "Incorrect indentation", 3: "missing colon"}
def __init__(self, line, file, code=0):
"*** YOUR CODE HERE ***"
def format(self):
"*** YOUR CODE HERE ***"
def add_code(self, code, msg):
"*** YOUR CODE HERE ***"
class ZeroDivisionError(Error):
"""
>>> err1 = ZeroDivisionError(273, "lab10.py")
>>> err1.write()
lab10.py:273 ZeroDivisionError : division by zero
"""
type = 'ZeroDivisionError'
def __init__(self, line, file, message='division by zero'):
"*** YOUR CODE HERE ***"
def format(self):
end = self.type + ' : ' + self.message
"*** YOUR CODE HERE ***"
```

Use OK to test your code:

`python3 ok -q Error`

Use OK to test your code:

`python3 ok -q SyntaxError`

Use OK to test your code:

`python3 ok -q ZeroDivisionError`

### Question 5: Checking account

We'd like to be able to cash checks, so let's add a `deposit_check`

method to our `CheckingAccount`

class. It will take a `Check`

object
as an argument, and check to see if the `payable_to`

attribute matches
the `CheckingAccount`

's holder. If so, it marks the `Check`

as
deposited, and adds the amount specified to the `CheckingAccount`

's
total.

Write an appropriate `Check`

class, and add the `deposit_check`

method
to the `CheckingAccount`

class. Make sure not to copy and paste code!
Use inheritance whenever possible.

See the doctests for examples of how this code should work.

The `Account`

class has been provided.

```
class Account(object):
"""A bank account that allows deposits and withdrawals.
>>> eric_account = Account('Eric')
>>> eric_account.deposit(1000000) # depositing my paycheck for the week
1000000
>>> eric_account.transactions
[('deposit', 1000000)]
>>> eric_account.withdraw(100) # buying dinner
999900
>>> eric_account.transactions
[('deposit', 1000000), ('withdraw', 100)]
"""
interest = 0.02
def __init__(self, account_holder):
self.balance = 0
self.holder = account_holder
self.transactions = []
def deposit(self, amount):
"""Increase the account balance by amount and return the
new balance.
"""
self.transactions.append(('deposit', amount))
self.balance = self.balance + amount
return self.balance
def withdraw(self, amount):
"""Decrease the account balance by amount and return the
new balance.
"""
self.transactions.append(('withdraw', amount))
if amount > self.balance:
return 'Insufficient funds'
self.balance = self.balance - amount
return self.balance
class CheckingAccount(Account):
"""A bank account that charges for withdrawals.
>>> check = Check("Steven", 42) # 42 dollars, payable to Steven
>>> steven_account = CheckingAccount("Steven")
>>> eric_account = CheckingAccount("Eric")
>>> eric_account.deposit_check(check) # trying to steal steven's money
The police have been notified.
>>> eric_account.balance
0
>>> check.deposited
False
>>> steven_account.balance
0
>>> steven_account.deposit_check(check)
42
>>> check.deposited
True
>>> steven_account.deposit_check(check) # can't cash check twice
The police have been notified.
"""
withdraw_fee = 1
interest = 0.01
def withdraw(self, amount):
return Account.withdraw(self, amount + self.withdraw_fee)
class Check(object):
"*** YOUR CODE HERE ***"
```

Use OK to test your code:

`python3 ok -q CheckingAccount`

## Submit

Make sure to submit this assignment by running:

`python3 ok --submit`